Solution the 100 number : 3n +1 on UVA

 

Problem: UVA Question 100 in briefly 

Input an integer number . The loop will moving by algorithm untill the number become 1. 
The number become 1 by looping 
How the times looping for number becoming 1 , print this  number .

For example:  
Input a number 22 . The 22 number becoming 1 the loop moving 16 times so the output is 16

Consider UVA problem number 100 algorithm 

Step 1 :    Input n

Step 2:     print n 

Step 3:     if n=1 the program stop

Step 4:     if n= ODD then n <------- 3n="" font="" nbsp="">

Step 5 :     else n <---------------- font="" n="" nbsp="">

Step 6:      Go to line 2 

Code of   3*n + 1  

#include
using namespace std;
int main(){
   int i,j,n,count=1,max;
    cin>>i>>j;
    max=0;
    cout<    while(i<=j){
        count=1;
        n=i;

    while(n!=1){
            if(n%2==0){
                n=n/2;
            }
            else{
                n=3*n + 1;
            }
            count++;
    }
    if(count>max){
        max=count;
    }
    i++;
    }
        cout<    return 0;

}